An immortal fumble by Androcles (20-Jun-2004)
Square roots revisited -- a MEGA META-Fumble!
| > | So you *are* serious about it: | > | https://home.deds.nl/~dvdm/dirk/Physics/Fumbles/NegSqrt.html | > | What a shame - I really thought you had at least *something* | > | going for you. | > | | > | Welcome in the club of Androcles: | > | https://home.deds.nl/~dvdm/dirk/Physics/Fumbles/SqrtAnswers.html | > | and Ken Seto: | > | https://home.deds.nl/~dvdm/dirk/Physics/Fumbles/SquareDiff.html | > | https://home.deds.nl/~dvdm/dirk/Physics/Fumbles/NegSquareRoot.html | > | | > | Dirk Vdm | > | > You are not welcome in my club, Dinky. Join your own. | > "sqrt(x^2) = -x for all x <= 0" - Dvm. | > http://www.androc1es.pwp.blueyonder.co.uk/Dinkyfumblezero.htm | > Of course I always knew you had nothing going for you. | > | > Androcles. | | So let's take an x <= 0, namely x = -9 | Then we have: | sqrt( x^2 ) = sqrt( (-9)^2 ) = sqrt(81) = 9 = - (-9) = - x | Wrong? | | And let's take another one, namely x = 0 | Then we have: | sqrt( x^2 ) = sqrt( (0)^2 ) = sqrt(0) = 0 = -0 = - x | Wrong? | | You really think this is wrong: | sqrt(x^2) = x for all x >= 0 | sqrt(x^2) = -x for all x <= 0 | ? | | Dirk Vdm "-sqrt(4) = -2" - Vdm "sqrt(x^2) = -x" - Vdm Priceless.... Androcles ROFLMAO! |
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| Fumble Index | Original post & context: guwBc.1580$eg4.13881472@news-text.cableinet.net |
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