"Daryl McCullough" <stevendaryl3016@yahoo.com> wrote in message news:d4962d0tep@drn.newsguy.com...
> Aleksandar Vukelja says...
> 
> >Okay, let's see. I created you correct ordering of events and made new
> >drawings with explanations
> >http://www.masstheory.org/daryl.pdf
> >
> >There's complete and accurate history of events.
> 
> No, it's not accurate (although they are pretty pictures). The
> left side is accurate, but not the right side.
> 
> Here are the mistakes:
>
>
> 1. The first picture on the right side should be labeled t' = -1.154
> 2. The second picture on the right side should be labeled t' = -.577

That's copy/paste error and is irrelevant, it does not change the concept. I
applied Lorentz transformation for the point which is x'=x = 0 only and the
time attributed to *that point* can be different from zero for the past and
future history of motion of *that particular point*.

Approach of taking as events arbitrary physical points in the same analysis
produces at least one paradox, which you also did not comment at all, and I
clearly presented it on the page 2 (activation of a bomb).

But as I claim that Lorentz tranasformation is invalid, then I don't care
what would be better way to use it. I can be satisfied with any approach for
as long as there is at least one paradox.

Aleksandar

> (The third and fourth pictures are labeled correctly).
> 3. The right knife cuts at time t'=-1.732, *not* t'=0
> 
> Your picture shows both knives cutting at t'=0 in frame K'.
> That is not what happens. The left knife cuts at t'=0, but
> the right knife doesn't.
> 
> In frame K, the right knife cuts at t=0, x=1. Therefore, we have
> in frame K'
> 
>     t' = gamma (t - vx/c^2)
>        = 2 (0 - .866)
>        = -1.732
> 
>     x' = gamma (x - vt)
>        = 2
> 
> This corresponds to a picture that you didn't draw, which looks like
> this (sorry for the ASCII):
> 
> 
>                                     |          |
>                                     |          |
>       --------------------
> 
> At time t' = -1.732, in frame K', we have the following locations:
> 
>       left end of rod : x' = 0
>       right end of rod : x' = 1
>       left knife : x' = 1.5
>       right knife : x' = 2
> 
> This is the time that the right knife cuts, not t' = 0.
> 
> --
> Daryl McCullough
> Ithaca, NY
>