Let a clock emit a frequency of 1 Hz be moving relative to
an observer with velocity 0.866c
t-vx/c^2
t' = _______________
sqrt(1-v^2/c^2)
ref (Electrodynamics, section 3)
= t * sqrt(1-v^2/c^2)
= 1 * 0.5
= 0.5 seconds
= 1 tick per 2 seconds
Consider Einstein's doppler shift, to be found in the
equation
1-cos(phi).v/c
nu' = nu. [________________]
sqrt(1-v^2/c^2)
ref (Electrodynamics, section 7)
Let phi = pi/2 or 3pi/2
1-0
nu' = 1 . _________________
0.5
= 2 ticks per second.
So according to Einstein,
0.5 = 2
Thus we have a proof by contradiction that v = 0.866c
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Fumble Index | Original post & context: yiaec.61354$Id.3138@news-binary.blueyonder.co.uk |
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