On Dec 31, 11:30 am, "Dirk Van de moortel" <dirkvandemoor...@hotspam.not> wrote: > seto...@att.net <seto...@att.net> wrote in message > 7626d34d-4f39-475e-bf9e-2a8ff94ce...@j10g2000vbe.googlegroups.com > > On Dec 31, 10:21 am, "Dirk Van de moortel" > > <dirkvandemoor...@hotspam.not> wrote: > > > seto...@att.net <seto...@att.net> wrote in message > > > 80560087-a39b-4629-9ada-88ade93e6...@t30g2000vbx.googlegroups.com > > > > On Dec 30, 9:16 pm, moro...@world.std.spaamtrap.com (Michael > > > > Moroney) wrote: > > > > > "seto...@att.net" <seto...@att.net> writes: > > > > > > On Dec 30, 10:43 am, Roger Onslow <roger.k.ons...@gmail.com> > > > > > > wrote: > > > > > > > So a negative value for time means a time value in the -x > > > > > > > direction .. you're a fucking moron > > > > > > > Fucking idiot you runt brothers insisted that delta(t)=-L/c. > > > > > > Once again, Dirk wrote the statement for the left side is t = > > > > > -L/(-c), NOT -L/c. You misquoted him. > > > > > The point is Dirk bag is wrong....c is isotropic and no (-) > > > > sign in froont of it in any location. > > > > The velocity represented by -c, toward negative x-coordinates, > > > in this case at location x = -L, has speed |-c| = c, and THAT is > > > isotropic. > > > If you want to put a (-) sign in front of c to indicate location > > No idiot would want to do that. > One puts a (-) sign in front of c to indicate the opposite DIRECTION > of the direction with positve x-values. Then you need to put a (-) sign in front of t to give -t to indicate the time interval in the direction of the negative x-value. > Since you don't know the difference between location and direction, Ok I mean direction....so sue me. Ken Seto > it is not surprising that you never understood the meaning of isotropy. > Do you even understand the meaning of "meaning"? > Come, say that this is "runt bogus gourmet puppy chow"! > > Dirk Vdm |
|
Fumble Index | Original post & context: 5165d275-aae1-4cef-9bb4-ad764c2abb6f@l19g2000yqc.googlegroups.com |