Dirk Van de moortel wrote:
> "Mike" <eleatis@yahoo.gr> wrote in message news:1128792154.526994.244990@g44g2000cwa.googlegroups.com...
> >
> > Phil Holman wrote:
> > > "Mike" <eleatis@yahoo.gr> wrote in message
> > > news:1128757877.413020.275340@o13g2000cwo.googlegroups.com...
> > > >
> > > > comtech wrote:
> > > >> Hi all,
> > > >>
> > > >> Somebody asked me an interesting question today:
> > > >>
> > > >> Suppose a juggler is continuously playing N balls, his own weight is
> > > >> W1
> > > >> pounds, and each ball weights W2 pounds... what is the AVERAGE weight
> > > >> of the system of the juggler and the balls?
> > > >>
> > > >> Can anybody show how to find the average weight?
> > > >>
> > > >> Thanks a lot!
> > > >
> > > > avgW = (W1+NxW2)/(N+1)
> > > >
> > > > Mike
> > >
> > > Very good Mike but that's the average weight of an item in the system.
> >
> > Hmmm... the average of x is x. I do not think it makes any sense to
> > speak of the average of one of the items in a system.
>
> Well, Mike aka Eleatis aka Undeniable aka Bill Smith,
> Phil did not speak of the average
>         "of one of the items in a system".
> He spoke of the average weight
>         "of an item in the system",
> and that is exactly what you have given, and what was
> not asked by the original poster at all.
>
> >
> > > The average weight of the system is the same as the weight of the
> > > system, avgW = (W1+N*W2). I think comtech is after the average force
> > > exerted vertically downwards by the juggler, which is probably  the
> > > same.
> >
> > No, I think we are confusing here quantities with average of
> > quantities. What you stated is the weight of the system.
>
> No, Mike aka Eleatis aka Undeniable aka Bill Smith,
> Phil stated his estimate of the average weight of the system of
> the juggler and the balls, which is what the original poster asked.
>
> > The
> > qualification of it as 'average" does not make any sense. Example:
> >
> > One pays $1 today to buy a cup of coffee and $2 to buy the same
> > tomorrow. The total paid is $3 (weight of system). The average price
> > paid is $1.5 (the average weight of the system).
>
> Perhaps you should have read the original question: "what is the
> average weight of the system of the juggler and the balls?"
> Perhaps you should have read it *before* your first answer, and
> then perhaps you should have read it before your *second*
> answer as well. Perhaps you should even read it even before
> your next answer.
>
> Now, as always, Mike aka Eleatis aka Undeniable aka Bill Smith,
> started digging yourself in. There is plenty of mud and shit waiting
> for you down there... Enjoy.

Imbecile, retarded, moron, psychotic Dirt of the Motel, I gave just one
answer and whether it is right or wrong I stock with it. You already
have given three answers stupid, idiot, psychotic, paranoid, physicist
wannabe.

Mike