"Paul B. Andersen" <paul.b.andersen@guesswhatuia.no> wrote in message news:4A1D9434.6080109@guesswhatuia.no... > Peter Riedt wrote: >> On May 27, 3:30 am, "Paul B. Andersen" >> <paul.b.ander...@guesswhatuia.no> wrote: >>> Peter Riedt wrote: >>>> Androcles, excellent and comprehensive derivation resulting in the >>>> answer 1=1. >>>> To which I like to add, if we add the speed of light to any other >>>> speed up to 300000km/sec, the answer is always 300000km/sec but if we >>>> subtract the speed of an object from the speed of light using the >>>> formula(c-v)/(1+c*v/c^2)[negative closing speed as in source and >>>> target approaching each other] the result is less than c-v e.g. >>>> for 300000km/sec-30km/sec the composite speed is not 299970km/sec but >>>> 299940.006km/sec. However if both c and v are 300000km/sec, they >>>> approach each other at a whopping c-v = 0km/sec! >>>> Peter Riedt >>> >>> The correct formula is: (c-v)/(1-c*v/c^2) = c >>> >>> -- >>> Paul >>> >>> http://home.c2i.net/pb_andersen/ >> >> Paul, agreed. >> (300000-300000)/(1-300000*300000/300000*300000)=0 > > No. > > 0/0 is undetermined, it's not zero > > But lim[(c-v)/(1-c*v/c^2)] = c when v -> c > > Note that the "speed addition formula" is a misnomer, > it is a speed tranformation formula. > If the speed of an object is u in an inertial frame K, > then this speed transforms to w in a frame K' which is > moving with the speed v relative to K, where > w = (u+v)/(1+u*v/c^2) > > The 'object' can be light (or a photon) and thus u = c, > but the speed of frame K' relative to frame K cannot be c, > so both u and v can never both be c. > v can however be arbitrary close to c, so the speed c > will always transform to c for all v. > > > -- > Paul Bwahahahaha! So much fun to see you squirming with simple algebra, Tusseladd, and how you hope to take a limit! "lim[(c-v)/(1-c*v/c^2)] = c when v -> c ".. ahahahahahahaha! Pity a spreadsheet doesn't agree with you! But then, you are proven liar as well as a idiot, anyway. http://www.androcles01.pwp.blueyonder.co.uk/E%5E2/DeriveMC2.htm |
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