Oh dear. I hadn't realized the moron from alt.moron had pathetically attempted to paraphrase me, since I have him on my not-worth-bothering-with list. Galilean Transforms. mapping from K to k x' = x-vt, t' = t. Mapping k -> K x = x'+vt, t = t'. Also we can change direction by letting u = -v. mapping K to k x' = x-ut, t' = t. Mapping k-> K x = x'+ut, t = t'. Thus I observe the Galilean Transforms to be symmetric. Now what is the idiot claiming, he can OBSERVE the Lorentz Transforms are SYMMETRIC? Let's see. mapping from K to k x' = (x-vt) / sqrt(1-v^2/c^2) t' = (t-vx/c^2) / sqrt(1-v^2/c^2) mapping from k to K, x = [ x' * sqrt(1-v^2/c^2)] + vt. t = [ t' * sqrt(1-v^2/c^2)] + vx/c^2 This is what Bile calls symmetric? |
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Fumble Index | Original post & context: EesKc.2059$ge2.22755463@news-text.cableinet.net |
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