> I will work with small steps again, like before.
> Do not object to something that is not written and that
> I might have said before. We start from scratch.
> If at some step you don't agree, stop there and skip
> everything that follows. Just say OK or not OKAY, and in the
> latter case, a short reason - NOT involving multiple observers
> in relative motion and clocks. Only ONE OBSERVER.
>
> 1C) A bomb explodes at a distance D and at time T according
> to me - but, again, you can use *your* favourite definitions
> and measurements of distance, speed and time.
> You freely choose some value for v of the bomb, but let's
> say you pick some v > 0, to signify that the bomb is going in
> some positive x-direction.
> So we know that the equation of motion of the bomb is
>         x - D = v (t-T)
>     where
>         t = time in my frame
>         v = velocity of bomb
>         x = distance of bomb to me at time t
>         D = given distance of explosion event
>         T = given time of explosion event
> in other words: at time t, the bomb is at distance
>         x = D + v (t-T),
> so indeed, at the given time T, the bomb is at the given
> distance D.
>
>
> 2C) If I want the bomb to explode at the given distance D
> at the given time T, then my outgoing signal must be present
> there and then, so the equation of motion of the outgoing
> signal is
>         x - D = c (t-T)
>     where
>         t = time in my frame
>         c = light speed (direction positive x-axis)
>         x = distance of outgoing signal at time t
>         D = given distance of explosion event
>         T = given time of explosion event
> in other words, at time t, the outgoing signal is at
> distance
>         x = D + c (t-T),

I am not quite with you here: from your equations obtained in 1C
(x=D+v(t-T)) and 2C (x=D+c(t-T)) one obtains  v=c.