Dirk Van de moortel wrote:

> > > You don't even need the acceleration part.
> > > Think about both twins jumping simultaneously on a moving
> > > frame that has velocity 0.9999c w.r.t. the original frame in
> > > which their clocks were synchronized. I.o.w. let them
> > > accelerate incredibly hard during an incredibly short time,
> > > i.o.w. ignore the accumulation of proper clock times during
> > > the acceleration phase. That makes it a bit easier.
> > > I asked David to calculate the age difference. It's not
> > > difficult. Can you give me two events, simultaneous in the
> > > final frame where the clocks of the twins give the same
> > > elapsed time?
> >
> > I say that the twins always remain in the same frame,
> > and their clocks always retain the same rate, and they
> > always age at the same rate.  Only in the view of the
> > non-accelerated observer are the twins ages
> > non-simultaneous, and the elapsed times different.

> I know. You said that before.
> But I asked you to actually prove it. Standard special
> relativity page 1: a few lines in little space-time diagram,
> a few events and their coordinates, and a simple
> transformation.
> All this to *show* what you say, to calculate and find
> zero difference in one frame and non-zero difference
> of the elapsed times, like you say, in the other frame.
> What is the *exact* difference? How many seconds?
> Remember, you don't need acceleration for this.
> I think David can't do it, although it is very simple.
> Can you?
> 
> Dirk Vdm

Your last challenge seems to contain a promise that,
if I don't satisfy this request, you are liable to not
only form the opinion that I don't because I can't,
but broadcast that opinion to everyone else as well.

Am I, then, to express my view in the manner that I
think will best serve it, or rather in the manner that
will best help you to form the best opinion of myself?

For anyone who wishes to exercise the prerogative
of every independent person to speak freely, what
other answer can there be to such an alternative
than that you must please yourself?

Alen