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"Paul B. Andersen" news:abhdro$s7h$1@dolly.uninett.no... > news:3cdbcb0e$0$3581$4c5ecdc7@news.erinet.com... > > The answers are as follows: > > 1. It is use by the observer to determine the clock time reading in the > > observed frame for a specific interval of absolute time in the observer's > > frame. > > Can you please show me how to use the Lorentz transform to > find the clock time reading of a 10 second interval of absolute time? Assuming the observer is more at rest then the LT becomes t'= (t - xv/c^2)/gamma When x=0 this equation is reduced to t'=t/gamma Therefore t'=10/gamma seconds Assuming that the observed frame is more at rest then the LT becomes t'=gamma(t + xv/c^2) When x=0 this equation is reduced to t'=gamma*t Therefore t'=10*gamma seconds > > > 2. It is use by the observer to calculate the light path length of a > > physical rod in the observed frame. > > I have a 1 metre long rod on my desk, Ken. > Can you please show me how to use the Lorentz transform > to find the light path length of the rod? Assuming the observer is more at rest then the LT becomes x'=gamma(x+vt) When t =0 this equation is reduced to x'=x*gamma Therefore the solution to your question is: x'=1*gamma meters Assuming the observed frame is more at rest then the LT becomes x'=(x-vt)/gamma When t=0 this equation is reduced to x'=x/gamma Therefore the solution to your question is: x'=1/gamma meters Ken Seto |
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Index Original post and context: 3cdd1048$0$3335$4c5ecdc7@news.erinet.com |