"Paul B. Andersen" <paul.b.andersen@hia.no> wrote in message
news:c0fji2$576$1@dolly.uninett.no...
>
> "Androcles" <jp006f9750@antispamblueyonder.co.uk> skrev i melding
> news:xfAWb.2321$MQ1.1596@news-binary.blueyonder.co.uk...
> >
> > "Paul Cardinale" <pcardinale@volcanomail.com> wrote in message
> > news:64050551.0402111519.4b11cd64@posting.google.com...
> > [snip]
> >
> > > Idiot.  If you would bother to LEARN the terminology, you might make a
> > > fool of yourself less often.  You have no clue what a coordinate
> > > transform is, do you?
> > >
> > > Paul Cardinale
> >
> > Explain it, then. I'm always willing to make a fool of any relativist.
> > Androcles
>
> Quite.
> When someone explains some elementary issue to Androcles,
> he will roll farting on the floor, thinking that when doing so,
> he is making fools of the relativists!
>
> An example of Androcles making a fool of me:
> Androcles wrote:
> | I found your statement "Let's call the period between each time the
> | satellites are adjacent T." so funny, Paul, it caused me to roll on the
> | floor laughing so hard I uncontrollably farted.
>
> (According to Androcles, a "period" is a dimensionless number
>  with the fixed value 2pi, and cannot have the dimension "time".)
> https://home.deds.nl/~dvdm/dirk/Physics/Fumbles/AreYouSure.html

====================
> You see, Androcles, as should be blatantly obvious
> from the experssion  sin(2*pi*t/P), the period P has
> the dimension time,

Time goes from -1 to 1 and runs backwards as well as forwards?
Are you sure about that?

> thus P/(2*pi) is never equal to dimensionless 1.

Astounding...
Definitely one for Dinky's list.
==========================
What Dinky the Deranged is careful to omit (as the impartial Google record
will show), is  that you, Paul, claimed

quote
In the following mathematical contra example where
Anrocles' claimed implication fails:
dtau/dt  =  1 - cos(2*pi*t/P), where P is the period
 so:   dtau/dt = 0 < 1 when t = nP, n integer.
 tau = t -(P/(2*pi))*sin((2*pi*t/P)
so:  tau = t   when t = nP, n integer
unquote
SO...
 tau = t -(P/(2*pi))*sin((2*pi*t/P)
and if we arbitrarily let P, a unit of time because it has dimension time,
have the value 12 months, there being 12 months in a year, and a month is a
unit of time the last I heard, then
 tau = t -(12/(2*pi))*sin((2*pi*t/12)
Now we could use t = 1, about the time it will take nTaul to have his
kittens,
so
 tau =1-(12/(2*pi))*sin((2*pi*1/12)

and its time for the calculator.
 tau =1-(1.91)*0.5 = 0.045
Oh... but wait.
I forgot nP, n integer.
Silly me.
Let's make P = 6 and n = 2, then nP = 12 as before.

> Keep making a fool of me, Androcles.
> You look so intelligent when you do.
>
> Paul

Sure, be glad to!

The time on an imaginary planet going the opposite way to the Earth,
otherwise in an identical orbit, is 1.35* days (per month of Earth time)
according to nTaul's contra-example, and this is blatantly obvious.
Mind you, I don't think being able to use a calculator make me look
especially intelligent, but it sure makes someone that cannot look a trifle
foolish. Of curse I might have made a blunder.  Why dont you check it for
me, or get Dinky to do it. He can publish my blunder on his page. Its up
there with asterisk between the 1. and the 5.
Androcles