Imagine a car 1 of mass m1 moving at v1 and a car 2 of mass m2 moving at -v2 wrt a tree situated along the road, hence when they collide, their total kinetic energy is (m1v1^2 + m2v2^2)/2. According to Einsteinian relativity, one can consider that car 1 is at rest, and that car 2 is moving at about V = -(v1 + v2) wrt car 1 (as v1 << c and v2 << c). Then, their total kinetic energy is m2V^2/2, which is of course different from (m1v1^2 + m2v2^2)/2, unless m1=0 and m2=0. Conclusively, Einsteinian relativity only applies to massless bodies, i.e. to mathematical points. Marcel Luttgens |
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Fumble Index | Original post & context: 1166783736.920732.127760@73g2000cwn.googlegroups.com |
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