"Dirk Van de moortel" <dirkvandemoortel@hotspam.not> wrote in message news:jq2qjl$kf8$1@speranza.aioe.org... > Indeed, writing LT and inverse: > x' = g ( x - v t ) [1] > t' = g ( t - v x ) [2] > x = g ( x' + v t' ) [3] > t = g ( t' + v x' ) [4] x' = g ( x - v t ) [1] Divide both sides of the equation by g: x'/g = x - v t [1.5] Add vt to both sides of the equation: x'/g + vt = x, or swapping sides, x = x'/g +vt [not 3] t' = g ( t - v x ) t'/g = t -vx t = t'/g + vx x = x'/g + v( t'/g + vx) = x'/g + vt'/g + v^2 x = (x' + vt')/g + v^2 x Hilarious! The fumbling fuckwit, Dork Van de Belgian Waffle, can't manage simple schoolboy algebra! ROFLMAO! |
|
Fumble Index | Original post & context: B47xr.1126491$nF6.355465@fx10.am4 |