Do you still maintain that the derivative of (1/2)mv^2 is not mv? Or should I ask, the indefinite integral of mv is not (1/2)mv^2 ? Or that I have forgotten the chain rule? Are you really just another relativist troll, or an intelligent being capable of admitting error? It is your integrity that is on the line, buddy, for all to see. Think carefully before you ignore, deny, or obfuscate. I'm calling, and the pot is quite large. If you want to bluff, raise. I'll raise, believe me. I have a royal flush in my hand, and I think you have nothing better than a full house, probably 2 pair. I don't want to rip you off, you are a decent guy. So I call. Thanks for the game. [snip unanswered correspondence] Androcles |
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Fumble Index | Original post & context: Yfkcd.93040$BI5.13999@fe2.news.blueyonder.co.uk |