On Feb 26, 12:23 pm, "Dirk Van de moortel"
<dirkvandemoor...@hotspam.not> wrote:
> ken...@att.net <seto...@att.net> wrote in message
> 
> 5a80a379-23c7-4932-98a4-866ab59a7...@f30g2000yqh.googlegroups.com
> 
> > On Feb 23, 1:18 pm, "Dirk Van de moortel"
> > <dirkvandemoor...@hotspam.not> wrote:
> > > ken...@att.net <seto...@att.net> wrote in message
> > > 07f8ada8-553b-423c-9a98-c6e1d97d7...@f2g2000yqh.googlegroups.com
> > > > On Feb 22, 10:09 am, "Dirk Van de moortel"
> > > > <dirkvandemoor...@hotspam.comnot> wrote:
> 
> [snip]
> 
> 
> 
> 
> 
> > > The speed of light has no "closing velocities". That is nonsense.
> 
> > OK....so what Einstein and PD said are nonsense.
> 
> > > I'm going to explain something.
> > > Forget for a moment what M' sees or measures.
> 
> > > We (and M) see this in the drawing:
> 
> > The drawing does not represent the real picture. Why? Because it is
> > an impossible gedanken.
> > The real gedanken:
> > M measures two events e1 and e2 in his frame to be simultaneous
> > after a time interval of L/c when the events happened simultaneously. It
> > is irrelevant the position of M' wrt M.....M can use the LT to predict
> > the time interval of simultaneity of two identical events e1' and
> > e2' in the M' frame and the result is delta(t').
> 
> You are a coward.
> You are a big coward.
> You are the biggest coward I have ever seen.


No you are the coward.....that's why you don't give any comment on my
realistic gedanken.

> 
> Here below you got it all on a plate, and don't even dare to begin to try
> to understand it.

Your premise is based on the assertion that M' is a few nonometer away
from M and that's an impossble situation. M and M' are real human
being.

> 
> 
> 
> 
> 
> 
> 
> > > 1) M' starts moving (at v) when a flash occurs behind him at A,
> > > with speed c at distance L.
> 
> > > After some time T, the flash reaches him in the back.
> > > He has then covered a distance v T.
> > > So, the light signal has covered a distance L + v T.
> > > But the light goes at c, so this distance is also c T.
> > > So, algebraicly we have
> > >     L + v T = c T
> > > and thus
> > >     L = c T - v T
> > >       = (c-v) T
> > > In the beginning, the distance between the A-signal and M' was L.
> > > After that time T, the distance between the A-signal and M' was 0.
> > > So, in the time T, the distance shrunk from L to 0 at a "rate" c-v.
> 
> > > 2) Likewise, when M' starts moving a flash occurs in front of him
> > > at B, with speed c at distance L.
> > > After some time U, the flash reaches him in the face.
> > > He has then covered a distance v U.
> > > So, the light signal has covered a distance L - v U.
> > > But the light goes at c, so this distance is also c U.
> > > So, algebraicly we have
> > >     L - v U = c U
> > > and thus
> > >     L = c U + v U
> > >       = (c+v) U
> > > In the beginning, the distance between the B-signal and M' was L.
> > > After that time U, the distance between the B-signal and M' was 0.
> > > So, in the time U, the distance shrunk from L to 0 at a "rate" c+v.
> 
> > > These numbers c-v and c+v are "called" the "closing velocities
> > > between M' and the signals, as calculated by M".
> > > Nothing moves at that velocity though. Some distance (according
> > > to us, and according to M) shrinks at those rates
> 
> > > 3) Now note that T and U cannot be the same, because we have
> > >     T = L / (c-v)
> > > and
> > >     U = L / (c+v)
> > > so they can only be equal if v = 0, which is not the case.
> > > you also see that
> > >     U < T
> > > which means that M' is first hit by the B-signal, and then by
> > > the A-signal.
> > > So M' first sees the B-signal, and then the A-signal.
> 
> > > Now, what does M' see and calculate?
> 
> > > 4) Initially, when the flashes started, he knows that they
> > > must have started in the front and on the back of his carriage,
> > > at equal distances because he knows that he is sitting in the
> > > middle, and he actually sees that the flashes came from
> > > the front and the back.
> 
> > > 5) He assumes that the speed of light is c.
> 
> > > 6) He first sees the B-signal and then the A-signal.
> 
> > > 7) Therefore, he must assume that the B-signal started
> > > before the A-signal, so the signals cannot have been
> > > emitted simultaneously.
> 
> > > So, go back to the text and read it a few more times.
> > > Until you get it.
> 
> Good grief, what a coward you are.
> 
> Dirk Vdm