Let p = pi/2 therefore p exists by definition. Let q = pi - p then p+q = pi but pi is not exactly divisible by 2, so q <> p. Let the difference be h such that q+h = p Therefore h = pi/2 - q and h exists. On my computer, pi = 3.1415926535897932384626433832795 p = 1.5707963267948966192313216916398 q = 1.5707963267948966192313216916397 h = 0.0000000000000000000000000000001 pi = p+(q+h) I have NEVER said pi/2 doesn't exist, moron Bonehead Green said h CAN be divided by 2 after I'd DEFINED it as the smallest number greater than zero and which cannot be divided. You're a LYING moron, papabozo. Lying triples your "moronity" grade when you are caught in a lie. papabozo, previous moronity 283. papabozo lied about me, present moronicity 849. 100 to 999, ULTRA HIGH MORONITY QUALITY. You can get much higher than this. |
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Fumble Index | Original post & context: wZPuq.44978$1Y4.44368@newsfe18.ams2 |