On Dec 30, 8:30 pm, YBM <ybm...@nooos.fr.invalid> wrote:
> Le 30.12.2011 18:41, seto...@att.net a écrit :
> 
> > Using the delta form of LT eliminate the need to make arbituary
> > assertion that x on the left hand side is -x
> 
> Let it be clear Ken. You've never study basic algebra, have you?
> 
> You probably left school at ten years old or so.
> 
> The basic of physics or math (no question of relativity here,
> just basic algebra, classical physics, etc.) if far beyond
> you abilities.
> 
> You don't ever know what writing a value as "x" (or "t" or whatever)
> means.
> 
> Do you realize how pathetic you are?

ROIFLOL....you have no answer why the delta form of LT refute the
claim of RoS and so 'you go on the attack.
In fact the coordinate form of LT also refute the RoS as follows:
Coordinates for the left side:
(-x1,t1)=(-L,-L/c)
LT for the left side:
t1'=gamma[(-L/c)- v(-L)/c^2)]
t1'=gamma[(-L/c)+vL/c^2]

Coordinate for the right side:
(x2,t2)=(L,L/c)
LT for the right side:
t2'=gamma[(L/c)-vL/c^2]

So you can see that t1' and t2' have the same numerical time value.
That means that both events are simultaneous....the signs switched
merely means that the position of the coordinates are at different
locations. What this mean is that the LT refute the claims of RoS. Gee
you runts of the SRians are stupid.