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> You don't understand. > t' = gt(1 - vV/c^2) > or > t'/t = g(1-vV/c^2) > is only valid for events *on the object* that satisfy > x = Vt. > > > If V = v then this reduces to > t'/t = g(1-v^2/c^2) > = 1/g > which is valid for all events that satisfy x=vt, > i.e. all events satisfying x'=0, i.e. all events on the > y'-z'-plane. > This equation > t'/t = 1/g > is of course equivalent with > t = gt' > which also follows from t = g(t'+vx'/c^2) and x'=0. > The relations x' = t' (V-v)/(1-vV/c^2) and t' = gt(1 - vV/c^2) are both false. The correct relations are x' = V't', where V' = (V - v) / (1 - vV/c^2) t' = t * sqrt(1 - v^2/c^2) |
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Index Original post and context: b45b8808.0208150552.e52c5af@posting.google.com |