Oh, BTW the correct specific power equation is,
q' = ¥[rho)t
q' = (¿c/4pi)µ[rho)t
Since power flux ¥ is related to momentum flux by,
¥ = ¿c/4pi
You failed one implicit test of your knowledge of details of a
LeSagian model!!! Hopefully you are NOT the author of that
reference :)
Paul Stowe
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| Fumble Index | Original post & context: e7p9711uog1audo357kr3c0cqgscvnsc87@4ax.com |