Oh, BTW the correct specific power equation is, q' = ¥[rho)t q' = (¿c/4pi)µ[rho)t Since power flux ¥ is related to momentum flux by, ¥ = ¿c/4pi You failed one implicit test of your knowledge of details of a LeSagian model!!! Hopefully you are NOT the author of that reference :) Paul Stowe |
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Fumble Index | Original post & context: e7p9711uog1audo357kr3c0cqgscvnsc87@4ax.com |