>> When *I* apply Pythagoras, I don't pretend the speed of light along >> the hypotenuse is the same as it is along the adjacent. >> I compute sqrt(c^2 + v^2), not c as a relativist does. >> Androcles > > The velocity is c, the *component* of that velocity along y is > sqrt(c^2 - v^2) Less than c, contradicting c invariant. You forgot to mutter "inertial frame". Androcles. |
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Fumble Index | Original post & context: C8AHd.179726$Z7.59099@fe2.news.blueyonder.co.uk |