And that, folks, is crackpottery in full action. V = v/(sqrt(1 - v^2/c^2), V Newtonian, hence unlimited. Let's try it. Let V =2c, c = 1. 2 = v/sqrt(1 -v^2) given. 4 = v^2 / (1-v^2) (squaring) v^2 = 4-4v^2 (multiply by 1-v^2 ) 0 = 4 - 4v^2 - v^2 (subtract v^2) = 4-v^2(4-1) = 4 -3v^2 3v^2 = 4 v^2 = 1.33 v = sqrt(1.33) = 1.155 > 1. |
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Fumble Index | Original post & context: 8xV3d.507$487.6223050@news-text.cableinet.net |