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F_net = F_Coulomb + F_Magnetic But classically F_net = (k'qq'/d^2) so we have: (k'qq'/d^2) = F_Coulomb + F_Magnetic, or (k'qq'/d^2) = (k'qq'/d^2) + F_Magnetic Let a = (k'qq'/d^2) and let b = F_Magnetic, substitution gives: a = a + b |
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Index Original post and context: 3D7CE362.4216C16E@yahoo.com |